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AlgebraGrade 10

The Quadratic Formula, Demystified

Integration Academy · June 15, 2026 · 6 min read

Every quadratic ax2+bx+c=0 ax^2 + bx + c = 0 is solved by one formula:

x=b±b24ac2a. x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.

It looks like something to memorize and fear. It's actually just completing the square performed on the general equation — once — so you never have to do it again.

The discriminant tells the story first

The piece under the root, b24ac b^2 - 4ac , is the discriminant. Before solving, it tells you how many real solutions exist:

  • b24ac>0 b^2 - 4ac > 0 : two real roots (the parabola crosses the x x -axis twice).
  • b24ac=0 b^2 - 4ac = 0 : one repeated root (it just touches the axis).
  • b24ac<0 b^2 - 4ac < 0 : no real roots (it floats above or below the axis).

A worked example

Solve 2x24x6=0 2x^2 - 4x - 6 = 0 . Here a=2, b=4, c=6 a = 2,\ b = -4,\ c = -6 .

x=(4)±(4)24(2)(6)2(2)=4±16+484=4±84. x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-6)}}{2(2)} = \frac{4 \pm \sqrt{16 + 48}}{4} = \frac{4 \pm 8}{4}.

So x=3 x = 3 or x=1 x = -1 . Always substitute one back to check — 2(9)126=0 2(9) - 12 - 6 = 0 . ✓

Tip

Compute the discriminant first. If it's negative, you can stop — there are no real solutions, and you've saved yourself the rest of the arithmetic.

Keep going. Put the idea to work in a course or test your reflexes with a math game.